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A liquid which is confined inside an adiabatic piston is suddenly taken from state 1 to state 2 by a single stage process. If the piston comes to rest at point 2 as shown. Then, the enthalpy change for the process will be: A. `DeltaH = (2gamma P_(0)V_(0))/(gamma -1)`B. `DeltaH = (3gamma P_(0)V_(0))/(gamma-1)`C. `DeltaH =- P_(0)V_(0)`D. none of these |
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Answer» Correct Answer - C |
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