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A load of 50Ω is connected in shunt in a 2 – wire transmission line of Z0 = 50Ω as shown in the figure. The 2 – port scattering parameter (s – matrix) of the shunt element is(a) \(\begin{bmatrix} - \frac{1}{2} & \frac{1}{2} \\[0.3em] \frac{1}{2} &- \frac{1}2 \\[0.3em] \end{bmatrix}\)(b) \(\begin{bmatrix} 0& 1 \\[0.3em] 1 &0 \\[0.3em] \end{bmatrix}\)(c) \(\begin{bmatrix} - \frac{1}{3} & \frac{2}{3} \\[0.3em] \frac{2}{3} &- \frac{1}3 \\[0.3em] \end{bmatrix}\)(d) \(\begin{bmatrix} \frac{1}{4} &- \frac{3}{4} \\[0.3em] \frac{1}{2} & \frac{1}4 \\[0.3em] \end{bmatrix}\) |
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Answer» (b) \(\begin{bmatrix}0& 1 \\[0.3em]1 &0 \\[0.3em]\end{bmatrix}\) The line is terminated with 50 ohms at the ends, so matched on both the sides thus S11= 0,S22 = 0 and S12 = S21 = 1 |
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