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A load of fles, groduces an extension of 2 mm in a wire 3m long and 1 mm in diameter. Calculate Young.s modulus of the material of the wire. |
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Answer» SOLUTION :SINCE `M=4kg, l =3 m, r=1//2 mm and Delta l=2mm` `Y=(Mgl)/(pir^(2)(Deltal))=(4xx9.8xx3)/((22)/(7)xx((1)/(200))^(2)((2)/(10^(3))))=7.48xx10^(10)N//m^(2)` Young.s modulus of the material of the wire `=7.48xx10^(10)N//m^(2)` |
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