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A load of mass 100 gm increases the length of wire by 10 cm. If the system is kept in oscillation, its time period is `(g=10m//s^(2))`A. `0.314 s`B. `3.14 s`C. `0.628 s`D. `6.28 s` |
Answer» Correct Answer - C `T=2pisqrt((M)/(k))=2pisqrt((0.100)/(10))=2pisqrt(1xx10^(-2))` `=2pixx10^(-1)=0.628s` |
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