1.

A load weighing 20,000 N is placed on a side with area 1000 "cm"^2. How much pressure would it exert on the ground?

Answer»

Solution :Force APPLIED by the load (F)=20,000 N
Area (A)= `1000 "cm"^2`
`=1000// (100xx100 m^2)=0.1 m^2`
PRESSURE (P)=F/A=`20,000 N//0.1 m^2`
`=2xx10^5` Pa


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