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A load weighing 20,000 N is placed on a side with area 1000 "cm"^2. How much pressure would it exert on the ground? |
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Answer» Solution :Force APPLIED by the load (F)=20,000 N Area (A)= `1000 "cm"^2` `=1000// (100xx100 m^2)=0.1 m^2` PRESSURE (P)=F/A=`20,000 N//0.1 m^2` `=2xx10^5` Pa |
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