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A long elastic spring is stretched by `2 cm` and its potential energy is `U`. If the spring is stretched by `10 cm`, the `PE` will beA. U/25B. 2UC. 5UD. 25U |
Answer» Correct Answer - D `(u_(2))/(u_(1)) =((1)/(2) kx_(2)^(2))/((1)/(2) kx_(1)^(2)) =((10)/(2))^(2)=25` `u_(2) =25u.` |
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