A long rectangular box is filled with CI_(2) (at wt 35.45) which is known to contain only CI^(35) and CI^(37) if the box could be divided by a partition and the two type of chlorine molecules put into the two compartments respectively calculate where should partition be made if the pressure on both sides are to be equal Is this pressure the same as original pressure ? .

A long rectangular box is filled with CI_(2) (at wt 35.45) which is kn

1.	A long rectangular box is filled with CI_(2) (at wt 35.45) which is known to contain only CI^(35) and CI^(37) if the box could be divided by a partition and the two type of chlorine molecules put into the two compartments respectively calculate where should partition be made if the pressure on both sides are to be equal Is this pressure the same as original pressure ? .
Answer» Solution :Since 34/45 is the average atomic weight of `""^(35)Cl` (at. wt. = 35)and `""^(37)Cl` (at. wt. = 37) we have, `(35 n_(1) + 37 n_(2))/(n_(1) + n_(2)) = 35.45`, where `n_(1)` and `n_(2)` are the number of molesof `""^(35)Cl` and `""^(27)Cl` respectively. `therefore (n_(1))/(n_(2)) = 3.44, n_(1) : n_(2) = 3.44 :1`. `therefore` ratio of LENGTHS is 3.44 : 1. Since the pressure on both the SIDES of the partition is EQUAL, the pressure before and after partition will be same (no. of moles PER unit volume being same).