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a long spring is stretched by 4 cm, and its potential energy is 80 J. If the spring is compressed by 2 cm, its potential energy will beA. 320 JB. 20 JC. 120 JD. 60 J |
Answer» Correct Answer - B `(E_(2))/(E_(1)) =(F_(2))/(F_(1)) xx (l_(2))/(l_(1)) =(yAl_(2))/(yAl_(1)) xx (L)/(L) xx (l_(2))/(l_(1)) =(l_(2)^(2))/(l_(1)^(2))` `therefore E_(2) =(4 xx 80)/(16) = 20J. ` |
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