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A long steel wire of length 'L' is suspended from the ceiling of a room. A sphere of mass 'm' and radius 'r' is attached to the lower end of the wire. The height of the ceiling is (L + 2r^(1) + 1). When the sphere is made to oscillate as a pendulum, its lowest point just touches the floor. The velocity of the sphere at the lowest point will be ( L gt gt r^(1), 1 and r is the radius of the wire) |
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Answer» `SQRT( (pir^(2) YE) /( m) - Lg)` |
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