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A long straight wire carrying a current `I` and a `II`- shaped conductor with siding connector are located in the same plane as shown in Fig. The connector of length `l` and resistance `R` sides to the right with a current induced in the loop as a function of separation `r` between the connector and the stragiht wire. The resistance of the `II`-shaped conductor and the self-induced of the loop are assumed to be negligible. |
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Answer» Field, due to the current carrying wire in the region, right to it, is directed into the plane of the paper and its magnitude is given by, `B = (mu_(0))/(2pi) (i)/(r)` where `r` is the perpendicular distance from the wire. As `B` is same length of the rod thus motinal e.m.f `xi_(i n) = |-int_(1)^(2) (vec(v) xx vec(B)) . d vec(l)| = vB l` and it is directed in the sense of `(vec(v) xx vec(B))` So, current (induced) in teh loop, `i_(i n) = (xi_(i n))/(R) = (1)/(2) (mu_(0) I vi)/(pi R r)` |
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