A long straight wire carrying current of `25A` rests on a table as shown in figure. Another wire PQ of length 1m, mass `2*5g` carries the same current but in the opposite direction. The wire PQ is free to slide up and down. To what height will PQ rise?

A long straight wire carrying current of `25A` rests on a table as sho

1.	A long straight wire carrying current of `25A` rests on a table as shown in figure. Another wire PQ of length 1m, mass `2*5g` carries the same current but in the opposite direction. The wire PQ is free to slide up and down. To what height will PQ rise?
Answer» Here, `I_1=25A, I_2=25A, l=1m, m=25g=25xx10^-3kg` In equilibrium position `mg=(mu_0)/(4pi)(2I_1I_2l)/(h)` or `h=(mu_0)/(4pi)(2I_1I_2l)/(mg)=(10^-7xx2xx25xx25xx1)/((2.5xx10^-3)xx98)=51xx10^-4m=051cm`

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A long straight wire carrying current of `25A` rests on a table as shown in figure. Another wire PQ of length 1m, mass `2*5g` carries the same current but in the opposite direction. The wire PQ is free to slide up and down. To what height will PQ rise?

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