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A longstick rests on the surface a person standing 10 m away the stick with what minimum speed an objectof masss 0.5 kg should he throuwn so that it hits the stick (Assume the coefficientof kinetic friction is 0.7 ) |
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Answer» Solution :Given: Distance (s) = 10 m Mass of the object (m) = 0.5 kg Coefficient of kinetic friction (`MU`) = 0.7 Work done in moving a body in horizontal SURFACE `omega = mu_R xx s = mu mg xx s ` This work done is EQUAL to INITIAL kinetic energy of the object `1/2 mv^2 = mu mg s ` `|v^2| = 2mug r s = 2 xx 0.7 xx 9.8 xx 10` `v^2 = 14 xx 9.8= 137.2` ` v = 11.71 ms^(-1)` |
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