A loop, carring a current i, lying in the plane of the paper, is in the field of a long straight wire with current `i_0` (inward) as shown in Fig. Find the torque acting on the loop.

A loop, carring a current i, lying in the plane of the paper, is in th

1.	A loop, carring a current i, lying in the plane of the paper, is in the field of a long straight wire with current `i_0` (inward) as shown in Fig. Find the torque acting on the loop.
Answer» Correct Answer - `(epsilon_(0)lB)/(sigma)` The net electric field `E=vec(E)_(1)+vec(E)_(2)` `impliesE=(sigma)/(2 epsilon_(0))+(sigma)/(2 epsilon_(0))+(sigma)/(epsilon_(0))` The net force acting on the electron is zero because it move with constant velocity `implies vec(F)_(n e t)=vec(F)_(c)_vec(F)_(m)=0` `implies\|vec(F)_(c)\|=\|vec(F)_(m)\|implieseE=evBimpliesv=(E)/(B)=(sigma)/(epsilon_(0)B)` `:.` The time of motion in side of the capacitor `=t=(l)/(v)=(epsilon_(0)lB)/(sigma)`

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A loop, carring a current i, lying in the plane of the paper, is in the field of a long straight wire with current `i_0` (inward) as shown in Fig. Find the torque acting on the loop.

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