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A loop of radius R and mass m is placed in a uniform magnetic field B with its plane perpendicular to the field. Current I is flowing in it. Now loop is slightly rotated about its diameter and released. Find time period of oscillation.A. `T=sqrt((pim)/(IB))`B. `T=sqrt((pim)/(IB))`C. `T=sqrt((2pim)/(IB))`D. `T=sqrt((pim)/(2IB))`

Answer» Correct Answer - 3


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