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A loop of wire having 50 turns carries a current of `10A` in anticlockwise direction. If diameter of loop is `10cm`, what is the magnitude and direction of magnetic moment of current loop? |
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Answer» Here, `N=50, I=10A`, `r=10/2cm=5xx10^-2m` `M=? From M=NIA=NI(pir^2)` `M=50xx10xx3*14(5xx10^-2)^2` `M=3*925Am^2` According to right hand thumb rule, direction of `vecM` is perpendicular to the plane of loop and away from observer. |
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