A lump of 0.10 kg of ice at -10°C is put in 0.15 kg of water at 20°C.How much water and ice will be found in the mixture when it has reached thermal equilibrium? Specific heat capacity of ice=0.50 kcal/kg and its latent heat of melting=80 kcal/kg

A lump of 0.10 kg of ice at -10°C is put in 0.15 kg of water at 20°C

1.	A lump of 0.10 kg of ice at -10°C is put in 0.15 kg of water at 20°C.How much water and ice will be found in the mixture when it has reached thermal equilibrium? Specific heat capacity of ice=0.50 kcal/kg and its latent heat of melting=80 kcal/kg
Answer» A lump of 0.10 kg of ice at -10°C is put in 0.15 kg of water at 20°C.How much water and ice will be found in the mixture when it has reached thermal equilibrium? Specific heat capacity of ice=0.50 kcal/kg and its latent heat of melting=80 kcal/kg

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A lump of 0.10 kg of ice at -10°C is put in 0.15 kg of water at 20°C.How much water and ice will be found in the mixture when it has reached thermal equilibrium? Specific heat capacity of ice=0.50 kcal/kg and its latent heat of melting=80 kcal/kg

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