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A lump of iron of mass 2 kg is heated from 40^(@)C" to "1000^(@)C. If the heat supplied is 192 k cal, find its thermal capacity. Find also the specific heat of iron. |
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Answer» Solution :Heat supplied `DeltaQ=192kcal=192xx10^(3)xx4.2J,` mass m = 2 kg , rise in TEMPERATURE `Deltat=1000-40=960^(@)C`. a) Thermal capacity of the LUMP of iron = `(DeltaQ)/(Deltat)=(192xx10^(3)xx4.2)/(960)=840J//K=` b) Specific heat of iron s = `(DeltaQ)/(mDeltat)=840/2=420Jkg^(-1)K^(-1)` |
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