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A lump of iron of mass 2 kg is heated from 40^(@) to 1000^(@)C . If the heat supplied is 192 kcal, find its thermal capacity. Find also the specific heat of iron. |
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Answer» Solution :HEAT supplied `Delta ` Q = 192 k cal `192 xx 10^(3) xx 4.2 `J, MASS m = 2 kg , rise in temperature `Delta t = 1000 - 40 = 960^(@)C`. (a) Thermal capacity of the LUMP of iron = `(Delta Q)/(Delta t) = (192 xx 10^(3) xx 4.2)/(960) = 840 `J/K = (b) Specific heat of iron s = `(Delta Q)/(m Delta t) = (840)/(2)= 420 j kg^(-1) K^(-1)` |
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