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InterviewSolution
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A machine delivers power to a body which is proportional to velocity of the body. If the body starts with a velocity which is almost negligible, then the distance covered by the body is proportional toA. `sqrt(v)`B. `3sqrt((v)/(2))`C. `v^(5//3)`D. `v^(2)` |
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Answer» Power `=Fv=m(dv)/(dt)(v)alphav` `rArr mv(dv)/(dt)=k_(0)v`, where `k_(0)=` constant `rArrm(dv)/(dt)=k_(0)rArrmv(dv)/(dx)=k_(0)` `rArr vdv=(k_(0))/(m)dx` `rArr` integrating both sides, `int_(0)^(v)vdv=(k_(0))/(m)int_(0)^(x)dx` `(v^(2))/(2)=(k_(0))/(m)x` Hence, displacement is proportional to square of instantaneous velocity. |
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