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A machine gun has a mass of 20 kg . It fires 35 g bullets at the rate of 4bullets per second, with a speed of 400 ms^(-1). What force must be applied to the gun to keep it in position ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of <a href="https://interviewquestions.tuteehub.com/tag/gun-1014044" style="font-weight:bold;" target="_blank" title="Click to know more about GUN">GUN</a>, M=20 kg<br/> Velocity of bullet, `v=400 ms^(-1)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> taken to fire one bullet, `t=1/4` second <br/> If F be the average force required to hold the gun in position , then <br/> `Fxxt`= change in momentum of gun or `Fxxt = MV[`:.` initial momentum of gun is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> ]<br/>`:. F=(MV)/t =(20xx0.7)/(1//4)N =56N`<br/>Aliter: Number of bullet <a href="https://interviewquestions.tuteehub.com/tag/fired-7262717" style="font-weight:bold;" target="_blank" title="Click to know more about FIRED">FIRED</a> per second, n=4 momentum given to the bullets per second = nmv<br/> Same momentum per second is gained by the gun . This gives the force acting on the gun and also the force applied to keep the gun in position .<br/> So , `F=nmv=4xx0.035xx400N=56N`</body></html>


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