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A magnetic field of `(4.0xx10^-3hatk)T` exerts a force `(4.0hati+3.0hatj)xx10^-10N` on a particle having a charge `10^-9C` and moving in te `x-y` plane. Find the velocity of the particle.A. `-75 hati+100 hatj`B. `-100 hati +75 hatj`C. `25 hati+2hatj`D. `2hati+25 hatj` |
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Answer» Correct Answer - a From Lorentz force, F=q(VxB) Given, `F=(4hati+3hatj) xx10^(-10)N, q=10^(-9)C` `B=4xx10^(-3) hatk T` `:. (4hati+3hatj) xx10^(-10) =10^(-9) (ahati+bhatj) xx(4xx10^(-3)) hatk` Solving, we get `a=-75, b=100 implies v =-75 hat i+100 hatj` |
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