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A magnetic field strength `(H) 3xx10^(3) Am^(-1)` produces a magnetic field of induction `(B)` of `12piT` in an iron rod. Find the relative permeability of iron ? |
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Answer» `mu=(B)/(H)=(12pi)/(3xx10^(3))=4pixx10^(-3)` `therefore mu_(r)=(mu)/(mu_(0))(4pixx10^(-3))/(4pixx10^(-7))=10^(4)` |
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