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A magnetic moment of `1.73BM` will be shown by one amongst the followingA. `[Ni(CN)_(4)]^(2-)`B. `TiCl_(4)`C. `[CoCl_(6)]^(4-)`D. `[Cu(NH_(3))_(4)]^(2+)` |
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Answer» Correct Answer - D `[Cu(NH_(3))_(4)]^(2+)` hybridisation `dsp^(2)` `Cu^(+2)-3d^(9)` has one unpaired `e^(-)` So magnetic moment `mu=sqrt(n(n+2))=sqrt(3)=` `sqrt(3)=1.73` |
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