A magnetising field of `1500 A//m` produces a flux of `2*4xx10^-5` weber in a bar of iron of cross-sectional area `0*5cm^2`. Calculate the permeability and susceptibility of the iron bar used.

A magnetising field of `1500 A//m` produces a flux of `2*4xx10^-5` web

1.	A magnetising field of `1500 A//m` produces a flux of `24xx10^-5` weber in a bar of iron of cross-sectional area `05cm^2`. Calculate the permeability and susceptibility of the iron bar used.
Answer» Correct Answer - `255`; `254` Here, `H=1500A//m`, `phi=24xx10^-5weber` `a=05cm^2=05xx10^-4m^2` `mu_r=?`, `chi_m=?` Now `B=phi/a=(2.4xx10^-5)/(05xx10^-4)=48xx10^-1T` `mu=B/H=(48xx10^-1)/(1500)=32xx10^-4` `mu_r=(mu)/(mu_0)=(32xx10^-4)/(4pixx10^-7)=0*255xx10^3=255` As `mu_r=1+chi_m :. chi_m=mu_r-1=255-1=254`

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A magnetising field of `1500 A//m` produces a flux of `2*4xx10^-5` weber in a bar of iron of cross-sectional area `0*5cm^2`. Calculate the permeability and susceptibility of the iron bar used.

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A magnetising field of `1500 A//m` produces a flux of `24xx10^-5` weber in a bar of iron of cross-sectional area `05cm^2`. Calculate the permeability and susceptibility of the iron bar used.