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A magnetising field of `2xx10^(3)Am^(-1)` produces a magnetic flux density of `8piT` in an iron rod. The relative permeability of the rod will beA. `10^(2)`B. `10^(0)`C. `10^(3)`D. `10^(4)` |
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Answer» Correct Answer - D `mu_(r)=(mu)/(mu_(0))=(B)/(mu_(0)H)` `=(8pi)/((4pixx10^(-7))(2xx10^(3)))` `mu_(r)=10^(4)` |
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