A man 4 times as old as his son. After 16 years, he will be only twice

1.	A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.
Answer» Let the present age of the son = x years. Therefore, the present age of his father = 4x years. So, after 16 years, Son’s age = (x + 16) and father’s age = (4x + 16) years According to question: ⇒ 4x + 16 = 2(x + 16) ⇒ 4x + 16 = 2x + 32 Transposing 2x to LHS and 16 to RHS, we get ⇒ 4x – 2x = 32 – 16 ⇒ 2x = 16 Dividing both sides by 2, we get ⇒ 2x/2 = 16/2 ⇒ x = 8 So, the present age of the son = x = 8 years, And the present age of the father = 4x = 4(8) = 32 years.

A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.

Answer»

Let the present age of the son = x years.

Therefore, the present age of his father = 4x years.

So, after 16 years,

Son’s age = (x + 16) and father’s age = (4x + 16) years

According to question:

⇒ 4x + 16 = 2(x + 16)

⇒ 4x + 16 = 2x + 32

Transposing 2x to LHS and 16 to RHS, we get

⇒ 4x – 2x = 32 – 16

⇒ 2x = 16

Dividing both sides by 2, we get

⇒ 2x/2 = 16/2

⇒ x = 8

So, the present age of the son = x = 8 years,

And the present age of the father = 4x = 4(8) = 32 years.