1.

A man bought a scooter and a car. He sold all of them at 30% profit. Scooter is sold at 10% profit. Cost price of scooter is 1/10 of the cost of car. Marked price of a car is ₹ 4,50,000. If he bought scooter at a discount of 20% on marked price and car at a discount of 10% on marked price then, what will be the ratio of marked price of scooter to the selling price of the car.

Answer»

25/264
25/268
35/260
34/260

Solution : C.P of CAR `= (90)/(100) xx 4,50,00 = ₹ 4,50,000`
C.P of scooter `= (1)/(10) xx 4,05,000 = ₹40,500`
MP of scooter = ₹50,625`
C.P of car and scooter = 4,50,000 + 40,500
`= 4,45,500`
S.P of car and scooter `= (130)/(100) xx 4,45,500 = ₹ 45,500 = ₹ 5,79,150`
S.P of car `= 5,79,150 -(110)/(100) xx 40,500`
`= 5,79,150-44,500`
`= 5,34,600`
Requried RATIO `= (50,625)/(5,34,600) = (25)/(264)`


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