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A man can swim with a speed of 4 "km h"^(-1)in still water. How lonu does he lake lo Cross a river 1 km wide if the 0.81 in river flows steadily at 3 "km h"^(-1)and he makes his strokes normal to the river current? |
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Answer» 5 min `t = ("width of river")/("SPEED of man") = (1 km)/(4 km h^(-1))=1/4h = 15 min` |
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