A man covers 5 m in 2 seconds ,taking a turn he covers 6 m in 4 second

1.	A man covers 5 m in 2 seconds ,taking a turn he covers 6 m in 4 seconds ,then his motion is _____ motion
Answer» Answer: We know that distance Travelled by uniformly accelerated body in n th s is given by S n =U+ 2 1 a(2n−1), where a is the acceleration of the body and u is the initial velocity it is given that S n =4S at n=3 ⟹4=u+ 2 5a .............. eq(1) S n =12 at n=5s ⟹12=u+ 2 9a ............... eq(2) solving eq(1) and eq(2), we get a=4m/s 2 and u=−6m/s Now we have to find velocity at t=5s we know that v=u+at ⟹v=−6+(4×5)=14m/s now distance travelled in next 3S can be calculated by S=ut+ 2 1 at 2 Note: now u=14m/s ⟹S=14×3+ 2 1 4(3 2 )=60m Explanation: rest motion..............

A man covers 5 m in 2 seconds ,taking a turn he covers 6 m in 4 seconds ,then his motion is _____ motion

Answer»

Answer:

We know that distance Travelled by uniformly accelerated body in n

s is given by

=U+

a(2n−1), where a is the acceleration of the body and u is the initial velocity

it is given that S

=4S at n=3

⟹4=u+

.............. eq(1)

=12 at n=5s

⟹12=u+

............... eq(2)

solving eq(1) and eq(2), we get

a=4m/s

and u=−6m/s

Now we have to find velocity at t=5s

we know that v=u+at

⟹v=−6+(4×5)=14m/s

now distance travelled in next 3S can be calculated by

S=ut+

Note: now u=14m/s

⟹S=14×3+

4(3

)=60m

Explanation: