1.

A man covers a certain distance on a scooter. Had he moved 6 km/h faster, he would have taken 30 minutes less. If he had moved 2 kmh"1 slower he would havetaken 30 minutes more. What is the distance ?

Answer»

6 KM



We can FIND the speed originally
S = X1X2(t1+t2)/t2t1-t1t2
= (6X2)(1/2 + 1/2)/6/2 - 2/2
= 12x1/3-1 = 12/2 = 6 kmh-1
DISTANCE = t1xS(S+x1)/x1= 1/2x6(6 + 6)/636/6 = 6 km



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