A man drags a block through 10 mon rough surface (mu=0.5). A force of sqrt(3) kN acting at 30^@ to the horizontal. The work done by applied force is

A man drags a block through 10 mon rough surface (mu=0.5). A force of

1.	A man drags a block through 10 mon rough surface (mu=0.5). A force of sqrt(3) kN acting at 30^@ to the horizontal. The work done by applied force is
Answer» zero 15 kJ 5 kJ 10 kJ Solution : The component of applied force F in the direction of MOTION is `F cos 30^@.` The work done by the applied force is `W = (F cos 30^@)S = SQRT(3) XX 10^(3) xx (sqrt3)/(2) xx 10 J = 15 xx 10^3 J = 15 kJ`