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A man goes 24 m West, again he goes 10 m North. Now at what distance is the man from his initialpoint?(A 34 m(C 26 m(B)17 m(D) 28 m |
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Answer» As man goes 24 West then 10 m North. This route forms right angled triangle with base b = 24 m, perpendicular p = 10 m and hypotenuse h =? Using pythagoras theoramh^2 = p^2 + b^2h^2 = 10*10 + 24*24h^2 = 100 + 576h^2 = 676h = 26 Therefore distance of man from starting point = 26 m (C) is correct option |
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