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A man having the genotype EEFfGgHH can produce P number of genetically different sperms, and a woman of genotype liLLMnNn can generate Q number of genetically different eggs. Determine the values P and QA. P = 4, Q = 4B. P = 4,Q = 8C. P = 8, Q = 4D. P = 8,Q = 8 |
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Answer» Correct Answer - B Types of gametes `= 2^(n)`, where n is number of heterozygous loci. Thus, man will produe `2^(2) = 4` types of gametes and woman will produce `2^(3) = 8` types of gametes. |
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