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A man invested Rs. 800 each in two banks for three years at simple interest. The difference between interest received after three years is Rs. 48, find the difference between the rates of interest.1. 4%2. 1%3. 2%4. 3% |
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Answer» Correct Answer - Option 3 : 2% Given: P = Rs. 800 each N = 3 years I2 – I1 = Rs. 48 Formula used: I = PRN / 100 Where P = Principal amount, R = Rate of interest in %, N = Number of years, I = Interest earned A = P + I Where A = Amount received Calculation: I2 – I1 = Rs. 48 ⇒ (PR2N/100) – (PR1N / 100) = 48 ⇒ PN(R2 – R1) / 100 = 48 ⇒ 800 × 3 (R2 – R1) / 100 = 48 ⇒ R2 – R1 = (48 × 100) / (800 × 3) ⇒ R2 – R1 = 16 × 100 / 800 ⇒ R2 – R1 = 2% ∴ required difference between the rate of interest is 2%. |
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