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A man is 25 m behind a bus, when bus starts accelerating at `2 ms^(-2)` and man starts moving with constant velocity of `10 ms^(-1)`. Time taken by him to board the bus isA. 2 sB. 3 sC. 4 sD. 5 s |
Answer» Correct Answer - D Displacement of man = displacement of bus + 25 or `10t=(1)/(2)xx2xx t^(2)+25` or `10t=t^(2)+25` Solving this equation, we get t = 5 s. |
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