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A man moves with a velocity `vecv_(1)` during time interval `t_(1)`. Then he moves with velocity `vecv_(2)` (which is perpendicular to the `vecv_(1)`) during time interval `t_(2)`. The incorrect statement is :A. `|Delta vecv| = sqrt(v_(1)^(2)+v_(2)^(2))`B. `s= |vecv_(1)t_(1)+vecv_(2)t_(2)|` = displacementC. `D = |vecv_(1)|t_(1)+|vecv_(2)|t_(2)` = distanceD. `vecv_(av) = (vecv_(1)+vecv_(2))/(2)` |
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Answer» Correct Answer - D A man ……………… `vecV_(av) = (vecV_(1)t_(1)+vecV_(2)t_(2))/(t_(1)+t_(2))` |
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