A man of 50 kg is standing on the school play ground at Trichy. The latitude of Trichy is 108^(@). Calculate the time (in hour ) to complete one rotation (one day) of the earth with the new angular speed.

A man of 50 kg is standing on the school play ground at Trichy. The la

1.	A man of 50 kg is standing on the school play ground at Trichy. The latitude of Trichy is 108^(@). Calculate the time (in hour ) to complete one rotation (one day) of the earth with the new angular speed.
Answer» Solution :Time TAKEN to complete one rotation of the earth (T)=? New ANGULAR speed `omega_(" new ") = 1.261xx 10^(-3)` rad/s `omega = (2pi)/(T) implies T=(2pi)/(omega) = (6.28)/(1.261xx10^(-3))` `=4.985 10^(3) SEC` `T= (4.985 10^(3))/(3600)= 1.4h`.