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InterviewSolution
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A man of `50 kg` mass is standing in a gravity free space at a height of `10m` above the floor. He throws a stone of `0.5 kg` mass downwards with a speed `2m//s`. When the stone reaches the floor, the distance of the man above the floor will beA. `9.9 m`B. `10.1 m`C. `1.0 m`D. `20 m` |
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Answer» Correct Answer - B Here, `m_(1)=50 kg, m_(2)=0.5kg` `u_(1)=?,u_(2)=2m//s` By momentum conservation, `m_(1)u_(1)+m_(2)u_(2)=0` `=u_(1)=(-m_(2)u_(2))/(m_(1))=(-0.5xx2)/(50)=(1)/(50)m//s` Negative sign is for upward motion of man. In gravity free space, time taken by stone to reach the floor, `t=(s)/(m_(1))=(10)/(2)=5s` Upward distance moved by the man `=u_(1)xxt` `=(1)/(50)xx5=0.1m.` `:.` Distance of man above the floor `=(10+0.1)m=10.1m` |
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