A man of mass 60kg sitting on ice pushes a block of mass of 12kg on ice horizontally with a speed of 5ms^(-1).The coefficient of friction between the man and ice and between block and ice is 0.2. If g =10 ms^(-2), the distance between man and the block, when they come to rest is

A man of mass 60kg sitting on ice pushes a block of mass of 12kg on ic

1.	A man of mass 60kg sitting on ice pushes a block of mass of 12kg on ice horizontally with a speed of 5ms^(-1).The coefficient of friction between the man and ice and between block and ice is 0.2. If g =10 ms^(-2), the distance between man and the block, when they come to rest is
Answer» 6m 6.5m 3m 7m Solution :`S_(1)=(V^(2))/(2mug)`, according to LAW of conservation of momentum, FIND `v^(1),S_(2)=(v^(1^(2)))/(2mug), S=S_(1)+S_(2)`