1.

A man of mass 70 kg stands on a weighing scale in a lift which is moving (a) upwards with a uniform speed of 10 m s 1, (b) downwards with a uniform acceleration of 5 ms^(2) , (c) upwards with a uniform acceleration of 5 ms^(2) . What would be the readings on the scale in each case ? (d) What would be the reading if the lift mechanism failed and it hurtled down freely under gravity ?

Answer»

Solution :MASSOF personm= 70kg
(a )when itmovesin upwarddirectinwithconstantvelocity
WEIGHT ofpersonrecorded in SPRINGBALANCE

W= mg
`=70 xx 10`
`=700 N`
Weighingscale will measure 70 kgweight
(b )whenliftis movingdownwithaccelerationin upwarddirectionresultantdirection
resultantaccelerationg= g- a

Weight recorded mg = mg- ma
`=70 (10-5)`
`=350N`
`: m = (mg )/( g ) = (350)/( 10)`
Weighingscalewillmeasure35 kgweight
(c ) Whenliftmoveswithupwardaccelerationwill be indownwarddirection
Weight recordedin springbalance
`:., mg = mg +ma`
`=70 (10 + 5)`
`70 xx 15`
1050 N
`:.= (mg)/( g) = (1050)/( 10) = 105 kg`
Weighingscalewillmeasure105 kgweight
(d )whenliftis fallingfreelythenpseudoaccelerationwill beupwarddirection
`:.`Weightrecorded
w=mg
`=m(0)`
`=0`
this iscalledweightlessness.


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