A man of mass M standing at a height h from the floor in a gravity free space throws a ball of mass m straight down with a speed u. When the ball reaches the floor, find the distance of the man above the floor.

A man of mass M standing at a height h from the floor in a gravity fre

1.	A man of mass M standing at a height h from the floor in a gravity free space throws a ball of mass m straight down with a speed u. When the ball reaches the floor, find the distance of the man above the floor.
Answer» Solution :When the MAN THROWS the ball with velocity U, he recoils with velocity V. mu = MV `V=(m u)/(M)` time taken by the ball to reach the GROUND `y=(h)/(u)` Distance moved by man in this time `t=v.t=(m u)/(M).(h)/(u)=(m)/(M).h` Height of man at the time the ball strikes the ground is `H=h+(m)/(M)h "" H=h(1+(m)/(M))`