1.

A man of mass `m` stands on a platform of equal mass `m` and pulls himself by two ropes passing over pulleys as shown in figure.If he pulls each rope with a force equal to half his weight ,his upwards acceleration would be A. `(g)/(2)`B. `(g)/(4)`C. `g`D. zero

Answer» Correct Answer - D
`F =4((mg)/(2))rarr upwards`
`W =2mgrarrdownwards`
`F = W, :. a =0` .


Discussion

No Comment Found

Related InterviewSolutions