A man reads 3/8 of a book on a day and 4/5 of the remainder on the sec

1.	A man reads 3/8 of a book on a day and 4/5 of the remainder on the second day. If the number of pages still unread are 40, then how many pages did the book contain?
Answer» Let the number of pages be p. Number of pages read on first day = 3p/8 Remaining pages = p - 3p/8 = (8p - 3p)/8 = 5p/8 Number of pages read on second day = 4/5 x 5p/8 = p/2 Now , remaining pages = p - [ 3p/8 + p/2] = p - [(3p + 4p)/8] = [p- 7p/ 8] = [(8p - 7p)/ 8] = p/8 According to the question p/8 = 40 ⇒ p = 40 x 8 ∴ p = 320

A man reads 3/8 of a book on a day and 4/5 of the remainder on the second day. If the number of pages still unread are 40, then how many pages did the book contain?

Answer»

Let the number of pages be p.

Number of pages read on first day = 3p/8

Remaining pages = p - 3p/8 = (8p - 3p)/8 = 5p/8

Number of pages read on second day = 4/5 x 5p/8 = p/2

Now , remaining pages = p - [ 3p/8 + p/2]

= p - [(3p + 4p)/8] = [p- 7p/ 8]

= [(8p - 7p)/ 8] = p/8

According to the question

p/8 = 40

⇒ p = 40 x 8

∴ p = 320

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A man reads 3/8 of a book on a day and 4/5 of the remainder on the second day. If the number of pages still unread are 40, then how many pages did the book contain?

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