A man saved ₹660000 in 20 years. In each succeeding year after the first yea he saves ₹ 2000 more than he saved in the previous year. How much did he save in the first year?

A man saved ₹660000 in 20 years. In each succeeding year after the f

1.	A man saved ₹660000 in 20 years. In each succeeding year after the first yea he saves ₹ 2000 more than he saved in the previous year. How much did he save in the first year?
Answer» Here, we have an AP in which ` S_(20) = 660000, d= 2000 ` and we have to find the value of a. Using the formula ` S_(n) = n/2 xx [ 2a +(n-1) xx 2000]` ` Rightarrow 10xx [ 2a + 19 xx 2000] = 660000` ` Rightarrow 20a + 380000 = 660000 rRightarrow 20a = 280000 Rightarrow a= 14000` Hence, the man saved ₹ 14000 in the first year.