1.

A man standing , observes rain falling with velocity of 20m//sat an angle of 30^(@) with the vertical Find out velocity of man so that rain appers to fall vertically Find out velocity of man so that rain again appears to fall at 30^(@) with the vertical.

Answer»

SOLUTION :`vecV_(m)=-vhati("let")`
`vecV_(R)=-10hati-10sqrt3hatj`
`vecV_(RM)=-(10-v)hati-10-sqrt3hatj`
`rArr-(10-v)=0`
(for vertcal fall , horizontal component MUST be zero)
(or)`v=10m//s`

`vecV_(R)=-10hati-10sqrt3hatj`
`vecV_(m)=-v_(x)hati`
`vecV_(RM)=-(10-v_(x))hati-10sqrt3hatj`
Angle with the vertical =`30^(@)`
`rArr TAN 30^(@)=(10-v_(x))/(10sqrt3)rArr v_(x) =20m//s`


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