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A man standing on the edge of the terrace of a high rise building throws a stone, vertically up with at speed of `20 m//s`. Two seconds later, an identical stone is thrown vertically downwards with the same speed of `20 m`,. ThenA. the relative velocity between the two stones remain, constant till one hits the groundB. both will have the same kinetic energy, when they hit the groundC. the time interval between their hitting the ground it `2s`D. if the collision on the ground is perfectly elastic, both will rise to the same height above the ground |
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Answer» Correct Answer - A::B::C::D a. `v_(1)=20-"gt"` `v_(2)=-20-"gt"(t-2)` `v_(1)-v_(2)=[20-"gt"]+[20+g(t-2)]=20m//s` Clearly it is time independent i.e., relative velocity between the two stones remains constant. b. in both the cases, the total energy remains the same. c. and d. these are simple concepts. |
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