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A man swims from a point A on the bank of a river if width 100 m. When he swims perpendicular to the water current, he reaches the other bank 50 m downstream. The angle to the bank at which he should swim, to reach the directly opposite point B on the other bank is. .

Answer» <html><body><p>`10^@` upstream<br/>`20^@` upstream<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^@` upstream<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^@` upstream</p>Solution :(d) <a href="https://interviewquestions.tuteehub.com/tag/refer-621103" style="font-weight:bold;" target="_blank" title="Click to know more about REFER">REFER</a> to (Fig. S5.68) (a), <br/> `tan <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> = (v_w)/(v_m) = (50)/(100) = (1)/(2) or v_m = 2v_w` <br/> Refer to (Fig .S5.68) (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>), <br/> `sin prop = (v_w)/(v_m) = (v_w)/(2 v_w) = (1)/(2)` <br/> or `theta = 30^@` <br/> So, it is `60^@` upstream. <br/> (a) <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C05_E01_106_S01.png" width="80%"/>,</body></html>


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