1.

A man whose mass is 90 kg stands on his feet on a floor. The total area of contact ofhis two feet with the floor is 0.036² m (Take,8 = 10 ms-²). How much is the pressureexerted by him on the floor?​

Answer»

25000 paExplanation:Given,Mass of the man,m = 90 kgsArea of contact,a = 0.036m²Acceleration DUE to gravity = 10 m/s²To FIND,Force of the manPressure exerted by him on the floorWe know,1.)F = maBut 'a' can be taken as 'g' because he isn't MOVING. Hence,F : mgF : 90 X 10F : 900N2.)P = F/Ap : 900/0.036p : 900/0.036/1000p : 900 x 1000/36p : 25000paHope it helps



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