InterviewSolution
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InterviewSolution
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A manis 7 times as old as his son now. Four years later, he will be 4 times as old as his son. Find their present ages. |
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Answer» Let present age of son = XAge of son before 5 years =X-5So, Present age of father = 7(X-5)+5 ……… (i)Age of son after 5 years = X+5Age of father after 5 years = 3(X+5)So, present age of father = 3(X+5)-5 ……….(ii)Equating age of father i.e. (i) and (ii)7(X- 5)+5 = 3(X+ 5)-57X – 35+5 = 3X + 15-57X-3X = 15 - 5 + 35 - 54X = 40X = 40/4 . X (son)= 10 , Father (3(10+5)-5)= 40 yrs |
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