1.

A manometer shows a pressure difference of 1 m of liquid mercury. Find ∆P in kPa.

Answer»

Hg : L = 1 m; ρ = 13 580 kg/m3 

The pressure difference ∆P balances the column of height L 

∆P = ρ g L = 13 580 kg/m3 × 9.80665 m/s2 × 1.0 m × 10-3 kPa/Pa

= 133.2 kPa



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