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A manometer shows a pressure difference of 1 m of liquid mercury. Find ∆P in kPa. |
Answer» Hg : L = 1 m; ρ = 13 580 kg/m3 The pressure difference ∆P balances the column of height L ∆P = ρ g L = 13 580 kg/m3 × 9.80665 m/s2 × 1.0 m × 10-3 kPa/Pa = 133.2 kPa |
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